思路：① 找初始左边界：第一个 nums[i] nums[i+1]；② 找初始右边界：最后一个 nums[i] < nums[i-1]；③ 求 [left,right] 内 min、max；④ 向左扩展：nums[left-1] minVal 则 left--；⑤ 向右扩展：nums[right+1] < maxVal 则 right++。长度 = right - left + 1。
Some GameCube flavor.
。谷歌浏览器【最新下载地址】是该领域的重要参考
Nature, Published online: 25 February 2026; doi:10.1038/s41586-026-10127-0，这一点在搜狗输入法2026中也有详细论述
This extends Google’s gatekeeping authority beyond its own marketplace into distribution channels where it has no legitimate operational role. Developers who choose not to use Google’s services should not be forced to register with, and submit to the judgement of, Google. Centralizing the registration of all applications worldwide also gives Google newfound powers to completely disable any app it wants to, for any reason, for the entire Android ecosystem.